49x^2-48=0

Solution for 49x^2-48=0 equation:

49x^2-48=0

a = 49; b = 0; c = -48;
Δ = b2-4ac
Δ = 02-4·49·(-48)
Δ = 9408
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9408}=\sqrt{3136*3}=\sqrt{3136}*\sqrt{3}=56\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-56\sqrt{3}}{2*49}=\frac{0-56\sqrt{3}}{98}
=-\frac{56\sqrt{3}}{98}
=-\frac{4\sqrt{3}}{7}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+56\sqrt{3}}{2*49}=\frac{0+56\sqrt{3}}{98}
=\frac{56\sqrt{3}}{98}
=\frac{4\sqrt{3}}{7}
$